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There are 7 yellow marbles, 6 blue marbles, 5 green marbles and 3 red marbles. What is the probability of drawing a red and then a blue marble WITHOUT replacement?

There are 7 yellow marbles, 6 blue marbles, 5 green marbles and 3 red marbles. What is the probability of drawing a red and then a blue marble WITHOUT replacement?
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There are 7 yellow marbles, 6 blue marbles, 5 green marbles and 3 red marbles. What is the probability of drawing a red and then a blue marble

WITHOUT replacement?

asked
User DropDrage
by
7.7k points

1 Answer

0 votes

Answer:

3/70

Explanation:

P(R,B) no replacement: 3/21 x 6/20 = 1/7 x 3/10 or 3/70 reduced

answered
User Peetya
by
7.4k points
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