Answer:
69.15%
Explanation:
You want the probability of a race time being less than 348 minutes if times are normally distributed with mean 319 minutes, and standard deviation 58 minutes.
Probability
The probability is found using the suggested resources. It will be ...
P(X<348) ≈ 0.6915
As a percentage, that is ...
0.6915 × 100% = 69.15%
The percentage of times shorter than 348 minutes is about 69.15%.
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Additional comment
The corresponding Z-score is (348-319)/58 = 0.500. Your table should give you the above value directly for that Z-score. No interpolation will be necessary.
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