Question

Solve the system of equations Y=2x+3. Y=x^2+3x+3

Answer 1

x= -1

y= 1

Explanation:

Set both equations equal to each other

2x+3=x^2+3x+3 then solve for x

2x=x^2+3x the 3 on either side cancel out

-x=x^2

-1=x

Then plug -1 in for one of the equations to solve for y

Y=2(-1)+3

Y=1