Answer:
3 NiSO₄(aq) + 2 (NH₄)₃PO₄(aq) ⇒ Ni₃(PO₄)₂ + 3 (NH₄)₂SO₄
Step-by-step explanation:
The question is missing but I think it must be about writing and balancing the equation.
Let's consider the unbalanced reaction that occurs when aqueous solutions of nickel(II) sulfate and ammonium phosphate are combined to form solid nickel(II) phosphate and a solution of ammonium sulfate. This is a double displacement reaction.
NiSO₄(aq) + (NH₄)₃PO₄(aq) ⇒ Ni₃(PO₄)₂ + (NH₄)₂SO₄
We will start balancing Ni atoms by multiplying NiSO₄ by 3.
3 NiSO₄(aq) + (NH₄)₃PO₄(aq) ⇒ Ni₃(PO₄)₂ + (NH₄)₂SO₄
Now, we have to balance S atoms by multiplying (NH₄)₂SO₄ by 3.
3 NiSO₄(aq) + (NH₄)₃PO₄(aq) ⇒ Ni₃(PO₄)₂ + 3 (NH₄)₂SO₄
Then, we need to balance N atoms by multiplying (NH₄)₃PO₄ by 2. This will be the balanced equation.
3 NiSO₄(aq) + 2 (NH₄)₃PO₄(aq) ⇒ Ni₃(PO₄)₂ + 3 (NH₄)₂SO₄