Question

I stg these bots with links keep answering my questions so can anyone help me with this problem?

How many grams of chlorine gas are needed to react with 2.50 liters of a 3.34 molar potassium bromide solution?
Cl2 + 2KBr → 2KCl + Br2

Answer 1

According to the website that I use to figure out things about science or chemistry and that stuff... The answer is 3.5 L KBr x 1.7 mol KBr solute / 1 L KBr solution x 1 mol Cl2 / 2 mol KBr x 70.9 g Cl2 / 1 mol Cl2 = 211 g Cl2.