Question

Solve the equation with logs on both sides of the equation. Please try to be quick

Answer 1

Answer: a=-1

Explanation:

Given

`\log_2 (-a+4)=\log _2(3-2a)`

As the base of both the logarithm is the same. Therefore, the value inside the logarithm is also the same

`\Rightarrow -a+4=3-2a\\\Rightarrow 2a-a=3-4\\\Rightarrow a=-1`

Thus, the value of a is -1