C12H26O + SO3+NaOH ----> C12H25NaSO4+ H2O If you need 11900 g of C12H25NaSO4 (Sodium Lauryl Sulfate) how many grams of C12H26O (Triglyceride) do you need?

Question

asked Dec 23, 2022 160k views

1 Answer

Rowland Shaw · Answer 1 · 2022-12-27T04:38:21+0000

Answer:

We can solve this by the method of which i solved your one question earlier

so again here molar mass of C12H25NaSO4 is 288.372 and number of moles for 11900 gm of C12H25NaSO4 will be = 11900/288.372

which is almost = 41.26 moles

so to get one mole of C12H25NaSO4 we need one mole of C12H26O

so for 41.26 moles of C12H25NaSO4 it will require 41 26 moles of C12H26O

so the mass of C12H26O = 41.26× its molar mass

C12H26O = 41.26×186.34

= 7688.38 gm!!

so the conclusion is If you need 11900 g of C12H25NaSO4 (Sodium Lauryl Sulfate) you need C12H26O 7688.38 gm !!

Again i d k wether it's right or wrong but i tried my best hope it helped you!!