Question

What is the [OH-] in a solution that has a pH = 9.23? *

O 1.7x10^5
O 8.2x10^-9
1.7x10^--5 M.

Answer 1

Answer: 1.7x10^-5

Step-by-step explanation:

pH + pOH = 14

14 - pH = pOH

14 - 9.23 = 4.77

pOH =4.77

[OH-] = 10^-pOH

= 10^-4.77

= 1.698243x10^-5

= 1.7x10^-5