Question

If 10.00 mL of 5.00M HCl, a strong acid, is added to 90.00 mL of pure water, the final volume of the solution is 100.00 mL. What is the pH of the solution?

Answer 1

pH = 0.30

Step-by-step explanation:

Hello there!

In this case, according to the given information about the acid, before we calculate the pH we must compute the final concentration of the acid after the dilution process:

`M_2=(10.00mL*5.00M)/(100.00mL)=0.5M`

Thus, since this strong acid is 100% ionized, the concentration of hydrogen ions will be also 0.5 M and therefore the pH:

`pH=-log(0.5)\\\\pH=0.30`

Best regards!