Question

Calculate the net force on the Fx and Fy
of
20 N
17 N
45.50
250

Answer 1

`F_(net)` is 26.25 N

Step-by-step explanation:

Given that:
`F_(x)` = 20 N,
`F_(y)` = 17 N.

This implies that the two forces are acting at right angle to each other. Thus applying the Pythagoras theorem, we have;

`F_(net)` =
`\sqrt{F_(x) ^(2) + F_(y) ^(2) }`

=
`\sqrt{(20)^(2) + (17)^(2) }`

=
`√(400 + 289)`

`F_(net)` =
`√(689)`

= 26.2488

`F_(net)` = 26.25 N

The net force is 26.25 N.