Question

There are 12 cans of soup in a carton. Each can has a

diameter of 8 cm and a height of 9 cm. How much paper, to
the nearest square centimeter, is needed to make labels that
wrap around each of the 12 cans? (Assume there is no
overlap.)

Answer 1

The required amount of paper is 2715.23
`cm^(2)`.

Explanation:

The cans of soup has a shape of a cylinder, so that;

The surface area around a cylinder = 2
`\pi`rh

Where: r is the radius of the can, and h is its height.

From the given question, diameter = 8 cm, then;

radius =
`(diameter)/(2)`

=
`(8)/(2)`

r = 4 cm

Surface area around one of the cans = 2 x
`(22)/(7)` x 4 x 9

= 226.2857

Surface area around one of the cans = 226.28
`cm^(2)`

So that, the total amount of paper required to make labels around each of the 12 cans can be determined by:

12 x 226.2857 = 2715.4284

The required amount of paper is 2715.23
`cm^(2)`.