Question

DUE SOON HELP ASAP

The TV measures 39 inches tall, and the length of its diagonal is 80 inches. What is the width of the TV? Round your answer to the nearest tenth and label your answer.

Your answer:

Answer 1

We're assuming the TV is a rectangle, meaning all corners have right angles.

From the given information, we have a right triangle with a height of 39 inches, hypotenuse, of 80 inches, and an unknown base width.

Using Pythagorean's theorem:

`a^2+b^2=c^2`

`b=√(c^2-a^2)`

c = 80 and a = 39

`b=√(80^2-39^2)`

`=√(4879)`

Using a calculator and rounding to the nearest tenth gives

`\approx 69.8 \text{ inches}`

Let me know if you need any clarifications, thanks!