Question

2. What is the mass of 5.33 x 10 moles of aluminum hydroxide?​

Answer 1

1865.5g

Step-by-step explanation:

first the chemical formular for ammonium hydroxide is NH4OH

its molarmass is given as N=14H=1O=16

so we have 14 +1(2) +16+1 =35

also no of moles = mass / molarmass

we have 5.33×10 = mass/35

therefore mass = 35 ×5.33×10 = 1865.5g