Final answer:
The combustion of 7.25 liters of C3H8 at STP produces 29.0 liters of H2O gas, according to the stoichiometry of the balanced chemical equation.
Step-by-step explanation:
Calculating the Volume of H2O Gas Produced from C3H8 Combustion
To calculate the volume of H2O gas produced when 7.25 liters of C3H8 are burned at STP using the provided equation:
C3H8 + 5O2 → 3CO2 + 4H2O
We see that the balanced chemical equation indicates that 1 volume of C3H8 produces 4 volumes of H2O. Therefore, if 7.25 liters of C3H8 are combusted, the volume of H2O produced can be calculated as follows:
(7.25 L C3H8) × (4 L H2O) / (1 L C3H8) = 29.0 L H2O
Thus, 29.0 liters of H2O gas are produced when 7.25 liters of C3H8 are burned at STP.