Question

A spider walks on the outside of a rectangular prism box from point A to B to C to D, then strings a web from point D to point E. What is the total distance of the spider’s path, rounded to the nearest tenth of an inch?

Answer 1

• 76 in

Explanation:

Use Pythagorean to solve diagonals.

Find the measure of each segment and add together:

• AB =
  `√(AE^2 + EB^2)` =
  `√((18 - 9)^2+12^2)` =
  `√(225)` = 15 in
• BC =
  `√(CE^2+BE^2)` =
  `√(18^2 + 12^2)` =
  `√(468)` = 21.6 in
• CD =
  `√(10^2+12^2)` =
  `√(244)` = 15.6 in
• DE =
  `√(10^2 + 12^2 + 18^2)` =
  `√(568)` = 23.8 in

Total distance:

• 15 + 21.6 + 15.6 + 23.8 = 76 in