Question

How many moles of NaCl are present in .05 L of 2.3 M NaCl solution?

Answer 1

N = 1.15 mol so choose dat one :) have a good day <3

Answer 2

n = 1.15 mol

Step-by-step explanation:

C = n/ V

n= C×V

n= 2.3× 0.5

n = 1.15 mol