Question

An unknown piece of metal absorbs 1350 J of heat as 55.0 g of the metal heats up from 20.0 oC to 47.0 oC

Answer 1

`C=0.91(J)/(g\°C)`

Step-by-step explanation:

Hello there!

In this case, according to the given information, it is possible to recall the equation to calculate the heat, Q, in these calorimetry problems as shown below:

`Q=mC(T_f-T_i)`

Thus, given the absorbed heat, mass and temperatures, we can easily calculate the specific heat of the metal as shown below:

`C=(Q)/(m(T_f-T_i))`

Then, by plugging in we obtain:

`C=(1350J)/(55.0g(47.0\°C-20.0\°C)) \\\\C=0.91(J)/(g\°C)`

Best regards!