Question

How many real solutions exist for this system of equations? Y = -x + 1 y = -x2 + 4x − 2 A. Zero B. One C. Two D. Infinite

Answer 1

Two solutions

Explanation:

Given the functions Y = -x + 1 y = -x² + 4x − 2

Since they are both y values, we will equate them to have:

-x+1 = -x² + 4x − 2

Equate to zero

x²-x-4x+1+2=0

x²-5x+3 = 0

Since the resulting equation is quadratic (highest degree being 2), hence there will be two solutions to the equation