Question

Two harmonic waves moving in the same direction are described by y1(x,t)=10.2sin(4x-700t) and y2(x,t)=10.2sin(4x-700t-7.9). What is the amplitude of the resultant wave at interference

Answer 1

14.42 units

Step-by-step explanation:

The waves are given as follows :

`y_1(x,t)=10.2\sin(4x-700t)\\\\y_2(x,t)=10.2\sin(4x-700t-7.9)`

We need to find the amplitude of the resultant wave at interference. Let it be A. So,

`A=√(10.2^2+10.2^2) \\\\=14.42\ units`

So, the amplitude of the resultant wave is equal to 14.42 units.