Question

What is the perimeter of ABC with vertices at A (-11,4) B(-7,8) and C (-4,4)

Answer 1

Explanation:

Using the distance formula,

`AB=\sqrt{(-11-(-7))^(2)+(4-8)^(2)}=√(16+16)=4√(2)\\AC=\sqrt{(-11-(-4))^(2)+(4-4)^(2)}=7\\BC=\sqrt{(-7-(-5))^(2)+(8-4)^(2)}=√(4+16)=2√(5)\\\\`

So the perimeter is
`4√(2)+7+2√(5)`