asked 181k views
4 votes
What is the Ka of a 0.0592 M solution of hydrofluoric acid (HF) with a pH of 6.90

asked
User Leighann
by
7.3k points

2 Answers

4 votes

Answer: 2.7 x 10^-13

Step-by-step explanation:

answered
User Sashaboulouds
by
8.8k points
6 votes

Answer:

2.7*10^-13

coefficient= 2.7

exponent= -13

Step-by-step explanation:

answered
User Vier
by
8.5k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.