Question

A traveling circus is moving in a train consisting of 20 cars, which were randomly adjoined to each other. 2 cars are carrying clowns, 2 cars house trapeze artists, 4 are reserved for lions, 4 - for bears, 4 - for elephants, and 4 for tents and provisions. What is the probability that no elephant or bear car precedes the first car with lions

Answer 1

the no elephant or bear car precedes the first car with lions is 0.60

Explanation:

The computation of the probability is shown below:

= 1 - (no depend or acrobat car precedes)

= 1 - (4 ÷ 20 + 4 ÷ 20)

= 1 - 8 ÷ 20

= 20 - 8 ÷ 20

= 12 ÷ 20

= 0.60

Hence, the no elephant or bear car precedes the first car with lions is 0.60

The same would be considered and relevant too