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16ef³÷8e²f= 24m²n³ _____= 2mn 2k³+k _____= 4k ​

16ef³÷8e²f= 24m²n³ _____= 2mn 2k³+k _____= 4k ​
asked 50.2k views
2 votes
16ef³÷8e²f=

24m²n³
_____=
2mn

2k³+k
_____=
4k



​

asked
User Stukselbax
by
8.1k points

1 Answer

4 votes

Answer:

Answer is below

Explanation:

16ef³÷8e²f=
(2f^(2))/(e)


(24m^(2) n^(3) )/(2mn) = 12m n^(2)


(2k^(3) +k)/(4k) =(1)/(2) k^(2) +(1)/(4)

answered
User BlueFox
by
7.8k points
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