Question

The area of a rectangle is 30m11n5 square units. If the length of the rectangle is 6m^n2 units, how many units wide is

the rectangle? (m + 0 and n +0)

Answer 1

Given:

The area of a rectangle =
`30m^(11)n^(5)`

Length of the rectangle =
`6m^4n^2`

To find:

The width of the rectangle.

Solution:

Area of a rectangle is:

`A=l* w`

Where, l is the length and w is the width of the rectangle.

Divide both sides by l.

`(A)/(l)=w`

`w=(A)/(l)`

On substituting the given values, we get

`w=(30m^(11)n^(5))/(6m^4n^2)`

`w=5m^(11-4)n^(5-2)`
`[\because (a^m)/(a^n)=a^(m-n)]`

`w=5m^(7)n^(3)`

Therefore, the correct option is A.