Question

a theater has 49 seats in the first row, 52 seats in the second row, 55 seats in the third row, and so on. how many seats are there in row 20

Answer 1

106

Explanation:

this question represents an arithmetic sequence problem where you can use this formula: a(n) = a(1) + d(n-1) where 'n' is value you're solving for, a(1) is the initial value, and 'd' is the common difference

a(20) = 49 + 3(20-1)

= 49 + 3(19)

= 49 + 57

= 106