Answer:
B. 36π in²
Explanation:
Given:
Volume = 54π in³
height (h) = 6 in.
Required:
Curved surface area of the can (area for the label needed to wrap around the can without overlapping)
Solution:
First, we need to find the radius (r) of the can.
Volume = πr²h
Plug in the given values and solve for r
54π = π*r²*6
54π = 6π*r²
54π/6π = r²
9 = r²
r = √9
r = 3 in
✔️Find the curved surface area:
Curved surface area = 2πrh
r = 3 in
h = 6 in
Plug in the values
C.S.A = 2*π*3*6
C.S.A = 36π in²