Question

A 2.5 V battery is connected to a small light

bulb with a resistance of 4.8 Ω .
What is the current in the bulb?
Answer in units of A.

Answer 1

Answer: I=0.52 A

Step-by-step explanation:

Given

Voltage is
`2.5\ V`

Resistance
`R=4.8\ \Omega`

Current is given by

`I=(V)/(R)`

`\Rightarrow I=(2.5)/(4.8)=0.52\ A`