asked 202k views
5 votes
In ABCD, the measure of ZD=90", the measure of ZB=31", and CD = 1,6 feet. Find

the length of BC to the nearest tenth of a foot,

asked
User Threxx
by
7.9k points

1 Answer

5 votes
3.1066≈3.1 feet that’s it
answered
User JoeCarpenter
by
8.0k points
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