Question

29 mols of na2So4 is how many grams

Answer 1

4118.2

Step-by-step explanation:

Given: 29 moles of na²
`So^(4)`

To find: In grams.

Solution: Wrong

If 1 na²
`So^(4)` is 142 grams, then 29 grams will be found if a set of fraction has been set up;

Let
be the variable

`(142)/(1) = (29)/(x)`

Cross multiply

`(142)/(29)`
`= 4.9`

Correct Solution

Multiply 29 by 142 = 4118

Answer 2

`4118\ g`

Step-by-step explanation:

`We\ are\ given,\\No.\ of\ moles\ of\ Na_2SO_4\ provided=29\ moles\\Hence,\\Now,\\Lets\ calculate\ the\ Gram\ Molecular\ Mass\ of\ Na_2SO_4.\\We\ know\ that,\\Gram\ Atomic\ Mass\ of\ Sodium(Na) \approx 23\ g\\Gram\ Atomic\ Mass\ of\ Sulphur(S) \approx 32\ g\\Gram\ Atomic\ Mass\ of\ Oxygen(O) \approx 16\ g\\Hence,\\We\ observe\ that,\\One\ molecule\ of\ Na_2SO_4\ is\ made\ up\ of\ 2\ Sodium\ Atoms,\ 1\\ Sulphur\ Atom\ and\ 4\ Oxygen\ Atoms.`

`Hence,\\Gram\ Molecular\ Mass\ of\ Na_2SO_4=2*(GAM\ of\ Na)+1*(GAM\ of\ S)\\+4*(GAM\ of\ O)\\=2*23+1*32+4*16\\=46+32+64\\=46+96\\=142\ g`

`Hence,\\We\ also\ know\ that,\\Mass\ of\ A\ Sample=No.\ of\ moles*Gram\ Molecular\ Mass\\Hence,\\Mass\ of\ 29\ moles\ of\ Na_2SO_4=29*142=4118\ g`