Question

1. A line has a slope of 6 and includes the

points (-1, q) and (0, -7). What is the
value of q?

Answer 1

q = -13?

Explanation:

the equation is y = mx + c

m is the gradient

c is the y-intercept

where the line crosses the y axis

If 6 is the gradient then the equation is

y = 6x + c

Find c by using the coordinates given:

-7 = ( 6× 0) +c

-7 = 0 + c

c = -7

the equation is y = 6x -7

Substitute the other coordinates to find q:

y or q = (6 ×-1) - 7

q = -6 -7

q = -13

Answer 2

q = - 13

Explanation:

Calculate the slope m using the slope formula and equate to 6

m =
`(y_(2)-y_(1) )/(x_(2)-x_(1) )`

with (x₁, y₁ ) = (- 1, q) and (x₂, y₂ ) = (0, - 7)

m =
`(-7-q)/(0+1)` = - 7 - q , then

- 7 - q = 6 ( add 7 to both sides )

- q = 13 ( multiply both sides by - 1 )

q = - 13