asked 230k views
0 votes
What volume would 75.0g of oxygen gas occupy

asked
User Natoya
by
7.5k points

1 Answer

3 votes

Answer:

Explanation: It is already known that 1 mole of the gas( or 32g of O2) is equivalent to 22.4 Litres of the oxygen gas. So, 8g is equivalent to = (22.4/32) × 8 = 5.6 L of the gas.

answered
User JamesE
by
7.6k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.