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Vertex form of x=y^2+6y+1

Vertex form of x=y^2+6y+1
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2 votes
Vertex form of x=y^2+6y+1

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User Maricel
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1 Answer

3 votes

x=(y+3)²−8 is the answer

answered
User Gleb Dolzikov
by
8.0k points
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