Question

How much water would I need to add to 700 mL of a 2.7 M KCl solution to make a 1.0 M solution?

Answer 1

`1190\ \text{mL}`

Step-by-step explanation:

`M_1` = Initial Concentration of KCl = 2.7 M

`V_1` = Volume of KCl = 1 M

`M_2` = Final concentration of KCl = 1 M

`V_2` = Amount of water

We have the relation

`M_1V_1=M_2V_2\\\Rightarrow V_2=(M_1V_1)/(M_2)\\\Rightarrow V_2=(2.7* 700)/(1)\\\Rightarrow V_2=1890\ \text{mL}`

The amount of water that is to be added is
`1890-700=1190\ \text{mL}`.