Question

Adam jogs at an average speed of 10km/h from his house to the airport. The airport is 7km away from his house. At what time must Adam leave his house in order for him to reach the airport at 7:20 am.

Answer 1

6:38am

Explanation:

From the question we are told that

Average speed
`V_(avg)=10km/h`

Distance traveled
`d=7km`

Generally the velocity across a distance is mathematically given given as
`V=d/t`

`10=(7)/(t)`

`t=0.7h\\t=42minutes`

Therefore

7:20-42 minutes =6:38am