asked 56.7k views
2 votes
A rocket is launched from a tower. The height of the rocket, y in feet, is

related to the time after launch, x in seconds, by the given equation.
Using this equation, find out the time at which the rocket will reach its
max, to the nearest 100th of a second.

y = 16x^2+ 238x + 81

2 Answers

2 votes
We need the max height as well
answered
User Seref Bulbul
by
7.8k points
6 votes

Answer: 7.44

Step-by-step explanation: DeltaMath

answered
User Harriette
by
8.5k points
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