Question

A 1.50x103-kilogram car is traveling east at 30 meters per second.

The brakes are applied and the car is brought to rest in 9.00 seconds.
A. Calculate the magnitude of the total impulse applied to the car to
bring it to rest. [Show all work, including the equation and
substitution with units.]
B. State the direction of the impulse applied to the car. [East or
West?]


PLEASE HELP!!!!

Answer 1

`39000\ \text{kg m/s}`

West

Step-by-step explanation:

m = Mass of car =
`1.3* 10^(3)\ \text{kg}`

t = Time = 9 seconds

u = Initial velocity = 30 m/s

v = Final velocity = 0

Impulse is given by

`J=m(v-u)\\\Rightarrow J=1.3* 10^3(0-30)\\\Rightarrow J=-39000\ \text{kg m/s}`

The magnitude of the total impulse applied to the car to bring it to rest is
`39000\ \text{kg m/s}`.

The direction is towards west as the sign is negative.