asked 67.6k views
5 votes
For the school play Kristi sold five tickets less than three times as many as Pudge salt ace sold twice as many is Kristi together for three students and 65 tickets how many did each one sell?

asked
User Eksortso
by
7.7k points

1 Answer

9 votes

Answer:

Pudge sold 8 tickets, Christi sold 19

tickets, Ace sold 38 tickets

Explanation:

x = Pudge

3x - 5 Christi

2(3x-5) = Ace

Let x, 3x - 5 and 2(3x-5) be the tickets

x + (3x- 5) +2(3x - 5) = 65

Combine like terms

x+ (3x - 5) + 6x - 10 = 65

4x -5+6x - 10 = 65

10x - 5-10 = 65

Transpose -5 and -10 and change their

signs

10x = 65 +5+ 10

Add

10x = 80

Divide both sides by 10

10x/10x = 80/10

x =8

Pudge sold 8 tickets.

Evaluate x as 8

3x-5

3(8)-5

24-5 19

Christi sold 19 tickets.

2(3x-5)

2(3(3)- 5)

2(24- 5)

2(19)= 38

Ace sold 38 tickets.

Checking:

x+ (3x - 5) +2(3x - 5) = 65

8+(3(8)-5) +2(3(8) - 5) = 65

8 +19 +38 = 65

65 =65

answered
User Pellul
by
8.8k points
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