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Factor completely: 4y^2 - y - 3

Factor completely: 4y^2 - y - 3
asked 111k views
13 votes
Factor completely: 4y^2 - y - 3

asked
User Jim Holden
by
8.2k points

2 Answers

7 votes

Answer:


(y - 1)(4y + 3)

Step-by-step explanation:


4 {y}^(2) - y - 3


4 {y}^(2) - 4y + 3y - 3


4y(y - 1) + 3(y - 1)


(y - 1)(4y + 3)

answered
User Andreihondrari
by
9.2k points
13 votes

Answer:


(4y + 3)(y - 1)

Step-by-step explanation:


4 {y}^(2) - y - 3


4 {y}^(2) - 4y + 3y - 3


4y(y - 1) + 3(y - 1)


(4y + 3)(y - 1)

answered
User Aleksander Monk
by
8.4k points
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