Two sides of a parallelogram are 49 feet and 78 feet. The measure of the angle between these sides is 59º. Find the area of the parallelogram to the nearest square foot.

Question

asked May 5, 2022 62.1k views

1 Answer

Jason Turan · Answer 1 · 2022-05-11T14:31:21+0000

Answer:

$A=3276\ ft^2$

Explanation:

Given that,

The sides of a parallelogram are 49 feet and 78 feet. The measure of the angle between these sides is 59º.

We need to find the area of the parallelogram.

Using trigonometry,

$\sin(59)=(h)/(49)\\\\h=\sin(59)* 49\\\\h=42.00\ ft$

We know that,

Area = base (b) × height (h)

So,

$A=78* 42.00\\\\A=3276\ ft^2$

So, the area of the parallelogram is equal to
$3276\ ft^2$ .