Question

1. How many grams are in 1.4 moles of Mg(NO3)2?

Answer 1

Step-by-step explanation:

molar mass of the compound = 24 + 2× 14+ 16×6

= 24 + 28 + 96

= 148g/mol

no of moles = given mass / molar mass of the compound

1.4 = given mass/ 148

1.4×148=given mass

207.2 g