Question

Find the inverse of h(x)= -x^5+2 step by step

Answer 1

Hi there!

`\large\boxed{y = \sqrt[5]{-(x-2)}}`

`h(x) = -x^(5) + 2`

Rewrite h(x) as y:

`y = -x^5 + 2`

Switch the x and y variables:

`x = -y^(5) + 2`

Isolate y by subtracting 2 from both sides:

`x - 2 = -y^5`

Multiply both sides by -1:

`-(x-2) = y^5`

Take the 5th root of both sides:

`y = \sqrt[5]{-(x-2)}`