Question

1) A spring with a spring constant of 0.70 N/m is stretched 1.5 m. What was the force? 2) The same spring is stretched 5 m. What was the force?​

Answer 1

1. K= F/∆l
2. F=K•∆l
3. ∆l=F/K
4. so we know that the K is 0.70N/m
5. the ∆l which is the elongation is 1.5 m
6. to find the force which is F u have to apply the formula.
7. by applying the formula you get 1.05N
8. for the second force you get 3.5N