Question

Joe is playing a game in which he has to roll two six-sided dice. In his past ten rolls, he has rolled a sum of one 2, two 5s, three 7s, two 8s, one 10, and one 12. The weighted mean of all of Joe’s dice rolls is __________.

Answer 1

The weighted mean of all of Joe’s dice rolls is 7.1.

Step-by-step explanation:

Since Joe is playing a game in which he has to roll two six-sided dice, and in his past ten rolls, he has rolled a sum of one 2, two 5s, three 7s, two 8s, one 10, and one 12 To determine the weighted mean of all of Joe's dice rolls, the following calculation must be performed:

(2 + (2 x 5) + (3 x 7) + (2 x 8) + 10 + 12) / 10 = X

(2 + 10 + 21 + 16 + 10 + 12) / 10 = X

71/10 = X

7.1 = X

Thus, the weighted mean of all of Joe’s dice rolls is 7.1.