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4 NH3 + 302 2N2 + 6H₂O 2.) a) A chemist burned 0.25 moles of ammonia gas (NH,) in the presence of excess oxygen pps to produce 2.95 grams of nitrogen gas (N2). Calculate the the…

4 NH3 + 302 2N2 + 6H₂O 2.) a) A chemist burned 0.25 moles of ammonia gas (NH,) in the presence of excess oxygen pps to produce 2.95 grams of nitrogen gas (N2). Calculate the the…
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2 votes
4 NH3 + 302

2N2 + 6H₂O
2.) a) A chemist burned 0.25 moles of ammonia gas (NH,) in the presence of excess oxygen
pps to produce 2.95 grams of nitrogen gas (N2). Calculate the theoretical yield of
nitrogen gas.

asked
User Alexandresecanove
by
8.1k points

2 Answers

5 votes

Answer:

I'm not sure but maybe 1 g ?!

4 NH3 + 302 2N2 + 6H₂O 2.) a) A chemist burned 0.25 moles of ammonia gas (NH,) in-example-1
answered
User Stafford
by
8.2k points
5 votes

Answer:

this is hard

Step-by-step explanation:

answered
User Louis Loo
by
8.0k points
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