Question

Hi can someone please help me with this question I've been stuck on it for soooo long!!

Answer 1

Let x=sinθ

2sin²θ = 5sinθ - 3

2x²=5x-3

2x²-5x+3=0

(2x-3)(x-1)=0

2x-3=0 or x-1=0

x=3/2 or x=1

sinθ=2/3 or sinθ=1

θ=arcsin(2/3) or θ=arcsin(1)

θ=0.729727656 or θ=1.57079633=π/2