Answer:
V₂ = 2.0 Liters at STP conditions
Step-by-step explanation:
Solving problem using the combined gas law
Given:
Case I Conditions Cast II Conditions
P₁ = 825mmHg P₂ = 760mm
V₁ = 2.30 Liters V₂ = ?
T₁ = 70°C + 273 = 343K T₂ = 0°C = 273K
Substitute into combined gas law assuming moles of gas remains constant; solve for unknown volume under case 2 conditions
P₁·V₁/n₁·T₁ = P₂·V₂/n₂T₂ => V₂ = P₁·V₁·T₂ / P₂·T₁ => note: in this solution, moles of gas remains constant as is disregarded in final calculation.
V₂ = (825mm)(2.3L)(273K) / (760mm)(343K) = 1.987 Liters (calculator answer) ≅ 1.9 Liters (2 sig figs based on given volume (V₁)
V₂ = 1.987 Liters ≅ 2.0 Liters (2 sig figs based on given volume (V₁)