Question

In ΔCDE, the measure of ∠E=90°, the measure of ∠C=43°, and CD = 95 feet. Find the length of EC to the nearest tenth of a foot.

Answer 1

69.5 is the answer I’m sure

Answer 2

9514 1404 393

Answer:

69.5

Explanation:

The useful trig relation in this case is ...

Cos = Adjacent/Hypotenuse

cos(43°) = x/95

x = 95×cos(43°) ≈ 69.5 . . . . feet