Question

A disc of moment of inertia 45kgm^2 is rotating with an angular velocity of 12rad/s.what will be its rotational kinetic energy?​

Answer 1

3240 J

Step-by-step explanation:

here moment of inertia (I)= 45kgm²

angular velocity (ω) = 12 rad/s

now KE = 1/2(Iω²)=1/2(45×12²)= 3240J