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What is the center of the circle: (x+3)^2+y^2=16 ?

What is the center of the circle: (x+3)^2+y^2=16 ?
asked 132k views
3 votes
What is the center of the circle: (x+3)^2+y^2=16 ?

asked
User Frank Kalis
by
7.6k points

1 Answer

2 votes

Answer:

the answer is (-3,0) or 4

Explanation:

answered
User Varun Maggo
by
8.2k points
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