asked 55.7k views
2 votes
A quantity with an initial value of 5700 decays exponentially

at a rate of 7.5% every 2 days. What is the value of the
quantity after 234 hours, to the nearest hundredth?

2 Answers

7 votes

Answer:

36.5625

Explanation:

so, if it decays at a rate of 7.5% every 2 days, and we have 234 hours, we do the following, 234/24, since there are 24 hours in a day, that gives us 9.75, "7.5% every 2 days" so we do this, 9.75/2 = 4.875

4.875 * 7.5 = 36.5625

i migt be wrong, but i'm pretty sure this is the answer, i'm not saying this is the answer like some people do, please let me know if i'm wrong.

answered
User Natim
by
8.4k points
7 votes

Answer:

3897.77

Explanation:

Decays 7.5%→r=0.075 (divide by 100)

Decays every 2 days: exponent of t/2

(where t is in days)

function- f(t)=5700(1−0.075) ^t/2

234 hours→234/24→9.75 days

Plug in t=9.75

f(9.75)=5700(1−0.075) ^9.75/2

3897.76635734

≈3897.77

answered
User Autodidact
by
8.5k points
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